The ellipse x^2/16 + y^2/9 = 1 has area equal to

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Multiple Choice

The ellipse x^2/16 + y^2/9 = 1 has area equal to

Explanation:
The area of an ellipse with semi-axes a and b is πab. This comes from starting with a circle of radius 1 and stretching by a in the x-direction and by b in the y-direction, which scales its area by ab, giving area πab for the ellipse. From the equation x^2/16 + y^2/9 = 1, the semi-axes satisfy a^2 = 16 and b^2 = 9, so a = 4 and b = 3. The area is π · 4 · 3 = 12π.

The area of an ellipse with semi-axes a and b is πab. This comes from starting with a circle of radius 1 and stretching by a in the x-direction and by b in the y-direction, which scales its area by ab, giving area πab for the ellipse.

From the equation x^2/16 + y^2/9 = 1, the semi-axes satisfy a^2 = 16 and b^2 = 9, so a = 4 and b = 3. The area is π · 4 · 3 = 12π.

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