Honors Mathematics 3 Practice Exam

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Solve x(x-2)(x+4)=0. List the solutions.

x ∈ { -4, 0, 2 }

When a product is zero, at least one factor must be zero. apply that to each factor in x(x−2)(x+4)=0:

- x = 0

- x−2 = 0 gives x = 2

- x+4 = 0 gives x = −4

All three values make the product zero, so the complete solution set is { −4, 0, 2 }. Presenting them in ascending order commonly shows them as −4, 0, 2.

x ∈ { 0, 2 }

x ∈ { -4, 2 }

x ∈ { -4, 0 }

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