In the ellipse x^2/36 + y^2/16 = 1 with a ≥ b, if a = 6 and b = 4, which are the coordinates of the major vertices?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $25.99Unlock all

Get ready for your Honors Mathematics 3 exam with our engaging quizzes. Use flashcards and multiple choice questions with explanations to enhance your study. Prepare effectively for the test!

Multiple Choice

In the ellipse x^2/36 + y^2/16 = 1 with a ≥ b, if a = 6 and b = 4, which are the coordinates of the major vertices?

Explanation:
The ellipse is in standard form x^2/a^2 + y^2/b^2 = 1 with a ≥ b, so its major axis lies on the x-axis. The major vertices are at (±a, 0), and the minor vertices are at (0, ±b). Here a^2 = 36 and b^2 = 16, so a = 6 and b = 4. Therefore the major vertices are at (±6, 0) and the minor vertices at (0, ±4). The description with major vertices (±6, 0) and minor vertices (0, ±4) matches.

The ellipse is in standard form x^2/a^2 + y^2/b^2 = 1 with a ≥ b, so its major axis lies on the x-axis. The major vertices are at (±a, 0), and the minor vertices are at (0, ±b). Here a^2 = 36 and b^2 = 16, so a = 6 and b = 4. Therefore the major vertices are at (±6, 0) and the minor vertices at (0, ±4). The description with major vertices (±6, 0) and minor vertices (0, ±4) matches.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy