Compute P(2) for P(x) = 2x^3 - 3x^2 + x - 5.

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Multiple Choice

Compute P(2) for P(x) = 2x^3 - 3x^2 + x - 5.

Explanation:
Evaluating a polynomial at a specific input means plugging that value into x and simplifying. For P(x) = 2x^3 - 3x^2 + x - 5, substitute x = 2: P(2) = 2(2)^3 - 3(2)^2 + (2) - 5. Compute the powers: (2)^3 = 8 and (2)^2 = 4. Then multiply: 2*8 = 16 and -3*4 = -12. So P(2) = 16 - 12 + 2 - 5. Combine the terms: 16 - 12 = 4; 4 + 2 = 6; 6 - 5 = 1. Therefore P(2) = 1.

Evaluating a polynomial at a specific input means plugging that value into x and simplifying. For P(x) = 2x^3 - 3x^2 + x - 5, substitute x = 2:

P(2) = 2(2)^3 - 3(2)^2 + (2) - 5.

Compute the powers: (2)^3 = 8 and (2)^2 = 4. Then multiply: 28 = 16 and -34 = -12. So P(2) = 16 - 12 + 2 - 5.

Combine the terms: 16 - 12 = 4; 4 + 2 = 6; 6 - 5 = 1. Therefore P(2) = 1.

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